-- -- Stack based Prolog inference engine -- Mark P. Jones November 1990 -- -- uses Haskell B. version 0.99.3 -- module Engine(prove) where import PrologData import Subst --- Calculation of solutions: -- the stack based engine maintains a stack of triples (s,goal,alts) -- corresponding to backtrack points, where s is the substitution at that -- point, goal is the outstanding goal and alts is a list of possible ways -- of extending the current proof to find a solution. Each member of alts -- is a pair (tp,u) where tp is a new subgoal that must be proved and u is -- a unifying substitution that must be combined with the substitution s. -- -- the list of relevant clauses at each step in the execution is produced -- by attempting to unify the head of the current goal with a suitably -- renamed clause from the database. type Stack = [ (Subst, [Term], [Alt]) ] type Alt = ([Term], Subst) alts :: Database -> Int -> Term -> [Alt] alts db n g = [ (tp,u) | (tm:*tp) <- renClauses db n g, u <- unify g tm ] -- The use of a stack enables backtracking to be described explicitly, -- in the following `state-based' definition of prove: prove :: Database -> [Term] -> [Subst] prove db gl = solve 1 nullSubst gl [] where solve :: Int -> Subst -> [Term] -> Stack -> [Subst] solve n s [] ow = s : backtrack n ow solve n s (g:gs) ow | g==theCut = solve n s gs (cut ow) | otherwise = choose n s gs (alts db n (apply s g)) ow choose :: Int -> Subst -> [Term] -> [Alt] -> Stack -> [Subst] choose n s gs [] ow = backtrack n ow choose n s gs ((tp,u):rs) ow = solve (n+1) (u@@s) (tp++gs) ((s,gs,rs):ow) backtrack :: Int -> Stack -> [Subst] backtrack n [] = [] backtrack n ((s,gs,rs):ow) = choose (n-1) s gs rs ow --- Special definitions for the cut predicate: theCut :: Term theCut = Struct "!" [] cut :: Stack -> Stack cut (top:(s,gl,_):ss) = top:(s,gl,[]):ss cut ss = ss --- End of Engine.hs